Easy
Given an integer array nums
, return true
if any value appears at least twice in the array, and return false
if every element is distinct.
Example 1:
Input: nums = [1,2,3,1]
Output: true
Example 2:
Input: nums = [1,2,3,4]
Output: false
Example 3:
Input: nums = [1,1,1,3,3,4,3,2,4,2]
Output: true
Constraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109
import java.util.HashSet;
import java.util.Set;
public class Solution {
public boolean containsDuplicate(int[] nums) {
Set<Integer> set = new HashSet<>();
for (int n : nums) {
if (set.contains(n)) {
return true;
}
set.add(n);
}
return false;
}
}