Medium
Given an integer array nums
that may contain duplicates, return all possible subsets (the power set).
The solution set must not contain duplicate subsets. Return the solution in any order.
Example 1:
Input: nums = [1,2,2]
Output: [[],[1],[1,2],[1,2,2],[2],[2,2]]
Example 2:
Input: nums = [0]
Output: [[],[0]]
Constraints:
1 <= nums.length <= 10
-10 <= nums[i] <= 10
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
@SuppressWarnings("java:S5413")
public class Solution {
List<List<Integer>> allComb = new ArrayList<>();
List<Integer> comb = new ArrayList<>();
int[] nums;
public List<List<Integer>> subsetsWithDup(int[] nums) {
Arrays.sort(nums);
this.nums = nums;
dfs(0);
allComb.add(new ArrayList<>());
return allComb;
}
private void dfs(int start) {
if (start > nums.length) {
return;
}
for (int i = start; i < nums.length; i++) {
if (i > start && nums[i] == nums[i - 1]) {
continue;
}
comb.add(nums[i]);
allComb.add(new ArrayList<>(comb));
dfs(i + 1);
comb.remove(comb.size() - 1);
}
}
}