Hard
A valid number can be split up into these components (in order):
'e' or 'E', followed by an integer.A decimal number can be split up into these components (in order):
'+' or '-').'.'.'.', followed by one or more digits.'.', followed by one or more digits.An integer can be split up into these components (in order):
'+' or '-').For example, all the following are valid numbers: ["2", "0089", "-0.1", "+3.14", "4.", "-.9", "2e10", "-90E3", "3e+7", "+6e-1", "53.5e93", "-123.456e789"], while the following are not valid numbers: ["abc", "1a", "1e", "e3", "99e2.5", "--6", "-+3", "95a54e53"].
Given a string s, return true if s is a valid number.
Example 1:
Input: s = “0”
Output: true
Example 2:
Input: s = “e”
Output: false
Example 3:
Input: s = “.”
Output: false
Example 4:
Input: s = “.1”
Output: true
Constraints:
1 <= s.length <= 20s consists of only English letters (both uppercase and lowercase), digits (0-9), plus '+', minus '-', or dot '.'.public class Solution {
public boolean isNumber(String s) {
if (s == null || s.isEmpty()) {
return false;
}
boolean eSeen = false;
boolean numberSeen = false;
boolean decimalSeen = false;
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
if (c >= 48 && c <= 57) {
numberSeen = true;
} else if (c == '+' || c == '-') {
if (i == s.length() - 1
|| (i != 0 && s.charAt(i - 1) != 'e' && s.charAt(i - 1) != 'E')) {
return false;
}
} else if (c == '.') {
if (eSeen || decimalSeen) {
return false;
}
decimalSeen = true;
} else if (c == 'e' || c == 'E') {
if (i == s.length() - 1 || eSeen || !numberSeen) {
return false;
}
eSeen = true;
} else {
return false;
}
}
return numberSeen;
}
}